I also like Math and Cryptography.Create templates to quickly answer FAQs or store snippets for re-use.A constructive and inclusive social network.
Let's use a Hash Set since we don't need to store a key-value pair.The previous algorithm has the best time complexity you can achieve so the following solutions will only improve space complexity.
LeetCode – Happy Number (Java) Write an algorithm to determine if a number is "happy". It's stupid because at first glance it seems very easy and doesn't have any programmatic relevance. }
The above image shows 11 such times.
} set.add(n); I also like Math and Cryptography.
Open source and radically transparent.We're a place where coders share, stay up-to-date and grow their careers. sum+=(n%10)*(n%10); Return True if n is a happy number, and False if not. A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. int sum =0; if(n==1) Both of them help in storing unique data. This is the second question in the LeetCode 30 Day Challenge.Write an algorithm to determine if a number n is "happy".A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. } return false; If so, we know that the original number is unhappy.In the last post, we came across 2 interesting data structures: Hash Maps and Hash Sets. Probably something like thisNow that you realize you might have missed something in the problem statement, you read it again and come across a very important hint:It says that an unhappy number will loop endlessly in a cycle. It's interesting because it can be used to learn something totally different but very useful.I hope you understood the 2 pointer method because it can be used to solve many unrelated and weird problems efficiently in terms of both time and space.I build random stuff with React and Node. while(!set.contains(n)){ HashSet
Return True if n is a happy number, and False if not. There are many other solutions that exploit various properties of Happy numbers but I want to use this as an opportunity to show an important concept and pattern used in Linked List problems.As mentioned in the Note, this solution will be based on a common pattern used in Linked List problems. This basically means it will run in a continuous loop. n=n/10; return true; So, all we need to do is check if we came across a repeated number other than 1.
Those numbers for which this process ends in 1 are happy numbers.Return True if n is a happy number, and False if not.Before I explain various ways to solve this problem, I want to say that this problem is kind of stupid and interesting at the same time. A hash could also be used to store the sums previously seen for O(1) lookup time. A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. while(n>0){ The times they coincide are weird which is why we don't notice them but they do.They coincide because the space they move through is limited in the circle and since one hand is faster they are bound to meet.The 2 pointers in a linked list are the same.
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